Question

Find the area of a rhombus whose diagonals are 15cm and 12cm long​

Answer 1

Solution:-

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$\Longrightarrow$ Here it is given in the question that the length of diagonals of a rhombus are 15 cm and 12 cm respectively. Now the question has asked us to to find out the area of the given rhombus. So, to find out the area of the rhombus we will apply the formula of area of rhombus when it's diagonals are given that is ½ × D₁ × D₂. The result which we will get after solving by applying the formula will be the area.

ANSWER:-

⪼ The area of the rhombus is 90 cm².

GIVEN:-

➤ Length of 1st diagonal (D₁) = 15 cm

➤ Length of 2nd diagonal (D₂) = 12 cm

TO FIND:-

⟹ Here we have to find the area of the rhombus

FORMULA:-

✺ Area of rhombus when it's diagonals are given = ½ × D₁ × D₂

SOLVING BY APPLYING THE FORMULA:-

• Finding the area of rhombus:-

☛ Area = ½ × 15 cm × 12 cm

☛ Area = ½ × 180 cm²

☛ Area = 1 × 180 cm² / 2

☛ Area = 180 cm² / 2

☛ Area = 180 cm² / 2 = 90 cm²

☛ Area = 90 cm²

Thus, we got the answer. The area of the rhombus is 90 cm².

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Answer 2

Given :

• One Diagonal (D)₁= 15cm
• Other diagonal (D)₂ = 13cm

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To find :

• Area of Rhombus

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Solution :

• As in the question two diagonals of Rhombus are given one of which measures 15cm and the other measures 12cm. By using the formula of Area of Rhombus 1/2 × D₁ × D₂ we can easily find the area of rhombus.

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Let D₁ = 15cm

And D₂ = 12cm

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${ \underline{ \boxed{ \red{ \bf{ Area \: of \: rhombus = \frac{1}{2} \times D_{1} \times D_{2}}}}}}$

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$\: \: \: \: \: \: \sf: \implies \dfrac{1}{2} \times 15 \times 12$

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$\: \: \: \: \: \: \sf: \implies15 \times 6$

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$\: \sf \: \: \: \: \: : \implies90 {cm}^{2}$

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${ \underline{ \boxed{ \color{blue} { \mathfrak{\therefore{Area~of~Rhombus~is \: 90 {cm}^{2} }}}}}}$

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