Math, asked by nourinhanan01, 3 months ago

Find the area of a rhombus whose diagonals are 4.8cm and 1.4cm.​

Answers

Answered by Ananya1098
0

We know,

Area of rhombus = \frac{1}{2} × d1 x d2

area =  \frac{1}{2} × 4.8 x 1.4

area = 2.8 cm^{2}

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Answered by Ladylaurel
2

Answer :-

  • The area of rhombus is 3.36cm².

Step-by-step explanation :

To Find :-

  • The area of rhombus

Solution :-

Given that,

  • The two diagonals of rhombus are 4.8cm and 1.4cm

As we know that,

Area of rhombus = 1/2 × d₁ × d,

Where,

  • d₁ = shorter length of diagonal
  • d₂ = longer length of diagonal

Here,

  • d₁ = 1.4cm
  • d₂ = 4.8cm.

According the question,

=> Area = 1/2 × d₁ × d₂

=> 1/2 × 1.4 × 4.8

Dividing 2 and 4.8 with 2

=> 1 × 1.4 × 2.4

=> 1.4 × 2.4

=> Area = 3.36

  • The area of rhombus is 3.36cm².

Know more :-

Perimeter of rhombus :-

  • Perimeter = 4 × side

Area of rhombus :-

We can find out the area of rhombus is three ways,

By using diagonals

  • Area = 1/2 × d₁ × d₂

By using base and height

Area = base × height

  • By using trinogeometry

Area = b² × sin(a)

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