Question

Find the area of a rhombus whose diagonals are 48 cm and 20 cm long.

Answer 1

$\huge\underline\mathrm{GivEn:-}$

Length of one diagonal = 48 cm

Length of another diagonal = 20 cm

$\huge\underline\mathrm{To\:Find:-}$

Find the area of rhombus = ?

$\huge\underline\mathrm{SoLution:-}$

We have given that, the formula to find the area of rhombus is :- $\frac{1}{2} \times d_{1} \times d_{2}$

Now, putting the given values in the formula

$\small\implies{\sf }$ $\rm{Area}$ = $\large{\rm {\frac{1}{2}}}$$\times$ 48 $\times$ 20

$\small\implies{\sf }$ $\rm{Area}$ = 48 $\times$ 10

$\small\implies{\sf }$ $\rm{Area}$ = 480 cm²

Thus, the area of rhombus is 480 cm²

$\huge\underline\mathrm{ThAnKs...}$

Answer 2

✬ Area = 480 cm² ✬

Step-by-step explanation:

Given:

• Length of first diagonal (d¹) of rhombus is 48 cm.
• Length of second diagonal (d²) of rhombus is 20 cm.

To Find:

• What is the area of the rhombus ?

Formula to be used:

• Area of rhombus = 1/2 x Product of its diagonals.

Solution:

$\implies \: (\frac{1}{2} \times d ^{1} \times d ^{2} )\: cm ^{2} \\ \\ \implies \: (\frac{1}{2} \times 48 \times 20 ) \: cm ^{2} \\ \\ \implies \: (48 \times 10) \: cm ^{2} \\ \\ \implies480 \: cm ^{2}$

Hence, the area of rhombus will be 480 cm²