Question

Find the area of a rhombus whose diagonals are length 20cm and

16.4cm.​

Answer 1

Step-by-step explanation:

Given

the length of diagonal are 20cm and 16.4cm

so,

Area of rhombus=1/2 * d¹* d²

=1/2* 20* 16.4

=10*16.4=>164cm²

I hope it will be helpful

Answer 2

Answer:

• Area of rhombus = 164 cm²

Step-by-step explanation:

Given:

• Diagonals of rhombus are 20 cm and 16.4 cm.

To Find:

• Area of a rhombus.

We know that,

$\longrightarrow \bf Area\;of\;rhombus=\dfrac{1}{2}\times d_{1}\times d_{2}\\ \\ \\ Where, \\ \\ \longrightarrow \sf d_{1} = 1st\;Diagonal = 20\;cm\\ \\ \longrightarrow d_{2}=2nd\;Diagonal = 16.4\;cm\\ \\ \\ {\underline{\sf Now,\;put\;the\;values\;in\;the\;given\;formula,\;we\;get,}}\\ \\ \\ \longrightarrow \sf Area\;of\;rhombus=\dfrac{1}{2}\times d_{1}\times d_{2}\\ \\ \\ \longrightarrow \sf Area\;of\;rhombus=\dfrac{1}{2}\times 20\times 16.4\\ \\ \\ \longrightarrow \sf Area\;of\;rhombus= 10 \times 16.4$

$\longrightarrow \sf Area\;of\;rhombus=164\;cm^{2}$

Hence, Area of rhombus = 164 cm².

Extra InFo:

What is Rhombus?

• A rhombus is a parallelogram whose all four sides equal and diagonals bisect each other at right angle.

• $\sf Area\;of\;rhombus=\dfrac{1}{2}\times d_{1}\times d_{2}$

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