Question

find the area of a rhombus whose diagonals are of lengths 20cm and 4.8cm

Answer 1

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Given :

• d₁ = 20 cm
• d₂ = 4.8 cm

To Find :

• Area of Rhombus

Formula used :

• ½ × d₁ × d₂ (Here, d₁ and d₂ are the lengths of the diagonals)

Solution :

Area of Rhombus = ½ × d₁ × d₂

= ½ × 20 × 4.8 cm

= ½ × 96 cm

= 1 × 48 cm

= 48 cm²

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Answer 2

Answer :-

• The area of the rhombus is 48 cm².

To find -

• The area of the rhombus.

Step-by-step explanation -

• Here, the lengths of the diagonals of a rhombus are given to us. We have to find its area!

We know that -

$\underline{\boxed{\sf{Area_{(rhombus)} = \dfrac{1}{2} \times {d}_{1} \times {d}_{2}}}}$

Where,

• d₁ = 20 cm.
• d₂ = 4.8 cm.

Applying the given formula -

$\mapsto \sf{Area = \dfrac{1}{2} \times {d}_{1} \times {d}_{2}}$

$\mapsto \sf{Area = \dfrac{1}{2} \times 20 \times 4.8}$

$\mapsto \sf{Area = \dfrac{1}{2} \times 96}$

Cancelling the numbers,

$\mapsto \sf{Area = 1 \times 48}$

$\mapsto \sf{Area = 48 \: cm^2}$

Hence -

• The area of the rhombus is 48 cm².

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