Question

Find the area of a rhombus whose each side measures 5 cm and whose one diagonal
measures 6 cm.

Answer 1

Answer:

A rhombus is also a parallelogram

Area of rhombus=base\times heightbase×height

Base=5cm

Height=4.8cm

Area=5cm\times4.8cm5cm×4.8cm

=24cm^2=24cm2

Also d_1=8cm\ \ d_2=?d1=8cm  d2=?

Area of rhombus=\frac{1}{2}\times product\ of\ diagonals21×product of diagonals

24=\frac{1}{2}\times8\times d_221×8×d2

24=4\times d_24×d2

d_2=\frac{24}{4}d2=424

=6cm

Hence,length of other diagonal is 6cm.

Answer 2

Answer:

30 cm^2 is the area of the rhombus.

Step-by-step explanation:

Since all the sides of a rhombus are equal, each side of the rhombus = 5cm.

By construction, let the rhombus be divided into two congruent triangles with the diagonal as the common arm of both triangles.

The area of one triangle = 1/2 * one side * diagonal = 1/2 * 5 * 6 = 15 cm^2

Since both the triangles are congruent, the areas of both triangles combined

= (15)(2) = 30 cm^2

Therefore, the area of the given rhombus is 30 cm^2.

Hope it helps! :)