Math, asked by mannjasteshwar11, 9 months ago

Find the area of a rhombus whose one side
is equal to 10 cm and the length of one of the
diagonals is 12 cm.​

Answers

Answered by spea0r
3

Answer:

Answer is 96cm^2

Step-by-step explanation:

First draw a rough figure and mark the measurements.

Then you will get a square with 4 triangles inside. Take 1 triangle which has both 10 cm and 12 cm.

Split 12 into 6 and 6 as diagonals are bisectors.

So each triangle has 10 as hypotenuse and 6 as perpendicular or base. Take out the other leg that is either the perpendicular or base through pythagoras theorem. It will come as 8cm. Now Double this 8cm to get the complete diagonal.

From here it is simple apply the formula for area of rhombus that is diagonal 1 * diagonal 2 whole upon 2

(12*16)/2 You will get 96 cm^2

Answered by Prabal5499
0

Answer:

96 cm^2

Step-by-step explanation:

By the pythagoras theorem

the other diagonal is 16 cm

then,

the area of rhombus is = (1/2 × 12 × 16)

= 96 cm^2

THANK YOU

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