Question

Find the area of a rhombus whose one
side is equal to 10 cm and the length of
one of the diagonals is 12 cm.
​

Answer 1

Rhombus ABCD

AB=10cm

BC=10cm

all sides of rhombus are equal.

Diagonal AC=12cm

So area of (tri ABC) by formula.

=

s(s−a)(s−b)(s−c)

, s is semi perimeter & a,b,c sides of triangles

s−

2

32

=16cm

Area =

16(16−10)(16−10)(16−12)

Area =

16×6×6×4

Area =48cm

2

Area (Rhombus ABCD) =48×2=96 cm2