Question

find the area of a rhombus whose one side measure 5 cm and one diagonal is 8 centimetre with solution

Answer 1

,hope it helps.................

Answer 2

Area of Rhombus is 24 $cm^2$

Step-by-step explanation:

• Properties of Rhombus says-

Diagonals are ⊥ Bisector

Therefore, the diagonal of 8 cm is divided into two segments 4 cm long. Using the Pythagorean Theorem and any of the right triangles to solve for x.

$5^2 = 4^2 + x^2$

$x^2 = 25 - 16$

$x^2 = 9$

x = 3

As per the formula for rhombus, Area, $A = \frac {1}{2} d_1d_2$

Where are diagonals

$d_1 = 8 cm$

$d_2 = 6 cm$

$A = \frac {1}{2} \times 8 \times 6$

$A = 24\ cm^2$