find the area of a rhombus whose one side measures 20 cm and one diagonal is 24 cm
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area of ∆ made by diagonal in rhombus
two sides=20m
20m
and diagonal 24 m
semiperimeter =32 m
hence area of ∆ by hero's formula
√[32(32-20)*(32-20)*(32-24)]
√[32*12*12*8]
=12*16
=192 m²
hence rhombus area =2∆
=192*2=384 m²
two sides=20m
20m
and diagonal 24 m
semiperimeter =32 m
hence area of ∆ by hero's formula
√[32(32-20)*(32-20)*(32-24)]
√[32*12*12*8]
=12*16
=192 m²
hence rhombus area =2∆
=192*2=384 m²
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