Find the area of a rhombus whose one side measures 5 cm and one diagonal as 8 cm.
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Answers
• Area of the Rhombus is 24cm²
According to the Question
It is given that ,
- Side of rhombus = 5cm
- Length of one diagonal ,d1 = 8cm
we have to calculate the area of rhombus .
As we know that all sides in rhombus are equal in length .
Firstly we calculate the another diagonal of rhombus .
As we know that diagonal are perpendicular bisector in rhombus . So we apply here the Pythagoras Theorem for calculating the another diagonal of the rhombus .
half of diagonal = 8/2 = 4cm
Let the another diagonal be x centimetres
➻ x² + 4² = 5² ⠀⠀⠀----(by Pythagoras Theorem)
➻ x² + 16 = 25
➻ x² = 25-16
➻ x² = 9
➻ x = √9
➻ x = 3 cm
Length of another diagonal = 2 × 3 = 6cm
Now, calculating the area of the rhombus .
- Area of Rhombus = 1/2 × d1 × d2
Putting the value we get
➻ Area of Rhombus = 1/2 × 8× 6
➻ Area of Rhombus = 1/2 × 48
➻ Area of Rhombus = 48/2
➻ Area of Rhombus = 24 cm²
- Hence the area of Rhombus is 24cm².
❒ Given :-
- One side of Rhombus = 5 cm
- Diagonal 1 = I cm
❒ To Find :-
- Area = ?
❒ Solution :-
⇝First finding second diagonal :
✏We know the Pythagoras theorem :
✏Second Diagonal :
⇝Now Area :
✏We know that :
✏Area :
➻Area = 1/2 × 49.95
➻Area = 1 × 24.975
➻Area = 24.975 or 25 cm(Approx)
⇝Therefore :
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