Find the area of a rhombus whose pe
80 cm and one of whose diagonals is24 cm
Answers
Answered by
0
Step-by-step explanation:
For a rhombus
Perimeter =80 cm
4 × side = 80
side= 80÷4
side= 20 cm
A rhombus has 2 diagonals that bisect each other.
Diagonal = 24 cm
half = 24÷2
= 12 cm
side= 20cm
By Pythagoras
D2 = 400-144( whole root)
= √256
= 15 cm
so, other diagonal= 15×2= 30 cm
area= 1/2 × d1× D2
= 1/2 × 24 × 30
= 12× 30
= 360 cm square
Similar questions