Question

find the area of a rhombus whose perimeter is 200 m and diagonal one is 80mtrs​

Answer 1

Answer:

Here is shortcut

Let sides be X

Perimeter= 200m (given)

Let sides be x°

=} so 4x=200m

=} X= 200/4=50 m.

so, sides will be 50 meters (each).

Now ,we know that the diagonals of a rhombus bisect each other perpendicularly (at 90°)

and 1/2 AC= 1/2*80=40 m

So. In ∆AOD, By Pythagoras theorem-

AD²=OD²+OA²

50²=OD²+40²

2500-1600=OD²

900= OD²

√900=OD

30 metres=OD.

,

Hence first diagonal (AC) is of 80 metres. and second diagonal (BD) is of 30 metres.

Area of Rhombus= 1/2*D¹*D²

so, 1/2*80*60

By solving this we find that Area will be 2400 metres ².

Hope this would be helpful.❤️