find the area of a rhombus whose perimeter is 200 m and one of the diagonal is 80m
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Answered by
4
Answer:
2400m²
explanation:
let one side be x
then , 4x = 200
x = 200/4
x = 50
given one diagonal = 80m
then,
(d/2)² + (d/2)²=x²
(d/2)²= 900
d = 2*30 = 60m
then , area of rhombus = d*d/2
=60*80/2
= 2400m². Ans
Answered by
2
2
2400m
is the answer of your question
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