Question

Find the area of a rhombus whose perimeter is 200m and one of the diagnols is 80m.

Answer 1

hloo

in rhombus all sides are equal.
formula of perimeter = 4 x side.
so = 200/4 = 50m.
diagnol = 80m.
in rhombus it can be divided into four equal triangles.


so we can find the area of one of those triangles by pythagoras theorem.

we have hypotenuse (side of the rhombus) = 50m
we have one side = 80/2 = 40m 
formula = hypotenues2 - other side2
=> 502 - 402 = other side 2
=>2500 - 1600 = 9000
root of 9000 = 30 .

we have to find the area of triangle
= 1/2 b x h
= 1/2 x 30 x 40
= 600m

Answer 2

Please mark brainliest..