Question

find the area of a rhombus whose perimeter is 32m and length of one diagonal is 10m​

Answer 1

Answer:

Step-by-step explanation:

perimeter of a rhombus=4a

4a=32

a=8

(a^2)=(d1/2)^2+(d2/2)^2

64=(10/2)^2+(d2/2)^2

64-25=(d2/2)^2

d2=2sqrt(39)

area=(1/2)*d1*d2

=(1/2)*10*(2sqrt(39))

=10sqrt(39)

Answer 2

Step by step explanation is given in the image attached.....