Question

find the area of a rhombus whose perimeter is 40 and diagonal is 60m

full explanation plz ​

Answer 1

Answer:

Step-by-step explanation:

Let ABCD be the rhombus, and let AC be its diagonal.

Let the diagonals meet at a point O.

Since the perimeter is 40 cm, each side of rhombus ABCD = 10 cm

                                   (All sides of a rhombus are equal)

AC = 60 cm (given)

⇒ AO = OC = 30 cm

In ΔAOB, using Pythagoras Theorem,

AB² = AO²+ OB²

⇒ 10² = AO² + 30²

⇒ 100 = AO² + 900

⇒ AO =  √-800

⇒ AO = 10√2 m

⇒ AC = 20√2 m

Area of rhombus = d1 * d2/ 2

                            = 20√2 * 60 / 2

                           =  600√2 m²

P.S: Pls draw the rhombus yourself....And not sure about the answer. Lemme know if I'm correct or wrong.