find the area of a rhombus whose perimeter is 80 m
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Answer:
400m^2
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Question:
find the area of a rhombus whose perimeter is 80 m
Answer:
The area of the rhombus is 384m²
Step-by-step explanation:
Given : Rhombus whose perimeter is 80 m and one of whose diagonal is 24m.
To find : The area of rhombus?
Solution :
Let p and q are the diagonals of rhombus.
Let a be the side of the rhombus.
Perimeter of rhombus = 4 × side
Side of the rhombus = a = √p² + q²
Area of rhombus is = a = 1/4p × √4P² -4p²
Where P is the perimeter P=80
And p is the diagonal = 24 m
Substitute the value in the formula,
A = 1/4p × √P² - 4p²
A = 1/4 × 24 × √ 80² - 4(24)²
A = 6 √6400 - 2304
A = 6 × 64
A = 384m²
Therefore, The area of the rhombus is 384m².
Hope you understand.
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