Find the area of a rhombus whose side 8cm and whose altitude is 0.5 dm.
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The answer is 31.2 cm²
GIVEN
Side of the rhombus = 8cm
Length of the altitude = 0.5 dm
TO FIND
Area of the rhombus.
SOLUTION
The above problem can be simply solved as follows;
Let the rhombus be ABCD
Let the diagonals intersect at 'O' .
It is known that the diagonals bisect eachother their point of intersection.
D₁ = AC
D₂ = BD
Applying pythagour theorem in ΔABO
AB² = AO² + BO²
8² = 5² + BO²
64 = 25 + BO²
BO² = 64 - 25
= 39
BO = √39
= 6.24 cm
Length of the diagonal = 2 × BO = 6.24 × 2 = 12.48
Formula to calculate area of the rhombus = (d₁ × d₂) ÷ 2
= (5 × 12.48) ÷ 2
= 62.4 ÷ 2
= 31.2cm²
Hence, The answer is 31.2 cm²
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