Find the area of a rhombus whose side is 20cm and altitude is 6cm. If one of its diagonals is 24cm long, find the length of the other diagonal.
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Answered by
36
Rhombus is also a parallelogram,
So, Area of Rhombus = base*height
= 20*6
= 120 cm²
We also know that, Area of Rhombus = product of diagonals/2
So, 120 = 24 * other diagonal/2
so, Length of other diagonal = 10 cm
So, Area of Rhombus = base*height
= 20*6
= 120 cm²
We also know that, Area of Rhombus = product of diagonals/2
So, 120 = 24 * other diagonal/2
so, Length of other diagonal = 10 cm
Answered by
8
we know that diagonal of a rhombus divides it into two congruent triangles with equal area
so are of triangle 1=1/2 bh
=20×6/2=60cm^2
similarly are of triangle 2 =60cm^2
so are of rhombus=are of triangle 1 + are of triangle 2=120cm^2
area of rhombus=d1d2/2
120=24×d2
d2=120/24
d2=5cm
so are of triangle 1=1/2 bh
=20×6/2=60cm^2
similarly are of triangle 2 =60cm^2
so are of rhombus=are of triangle 1 + are of triangle 2=120cm^2
area of rhombus=d1d2/2
120=24×d2
d2=120/24
d2=5cm
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