Question

find the area of a rhombus whose side is 20cm and one of its diagonal is 32cm pls guys help me with this question 50points​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

Answer

R.E.F image

Find Area of Rhombus

Side = 20 cm

one diagonal is 24 cm

→□ABCD BC = 24 cm, so, BM=MC=

2

24

=12cm

→ diagonals AD=AM+MD

→In△AMC, using Pythagoras theorem

AC

2

=AM

2

+MC

2

(20)

2

=AM

2

+(12)

2

AM

2

=(20)

2

+(12)

2

=400−144

AM

2

=256

AM=

256

AM=16cm

→AM=MD=16cm

→ Area of Rhombus =

2

1

× Product of diagonal

=

2

1

×(AD.BC)

=

2

1

×((16+16).24)

=

2

1

×32×24

=384cm

2