find the area of a rhombus whose side is 5 cm and whose altitude is 4.8cm
one of its diagonals is 8cm long, find the length of the other diagonal
Answers
Answer:
Area of rhombus =24
Length of another diagonal is 6
Step-by-step explanation:
Side of a rhombus(s) =5
Altitude of a rhombus(h) =4.8
Length of one diagonal(d1)=8
Area of rhombus =s*h
= 5*4.8
= 24
Area of rhombus = d1*d2÷2
24=8*d2÷2
24*2=8*d2
48=8*d2
48÷8=d2
6=d2
i.e d2=6
Answer:
Given:-
The area of rhombus, side is 5cm and altitude is 4.8cm and one of its diagonal is 8cms.
To Find:-
Find the length of other diagonal. ....?
Solutions:-
Let the length of the other diagonal of the rhombus be x.
A rhombus is a special are of a parallelogram.
The area of a parallelogram is the product of its base and height.
Area of the Rhombus = base × height
= 5cm × 4.8cm
= 24cm²
Area of rhombus = 1/2 (products of its diagonal)
- ⟹ 24cm² = 1/2 × (8cm + x)
- ⟹ x = 24 × 2 / 8
- ⟹ x = 48/8
- ⟹ x = 6cm
Hence, the length of the other diagonal of the Rhombus is 6cm.
Some Important:-
A rhombus all side are equal.
A rhombus opposite angle are equal.
A rhombus the sum of adjacent angle angle supplementary i.e. (<A + <D = 180°).
A rhombus, each diagonal of a rhombus divides it into two congruent triangle.
A rhombus, if one angle is right, then all angle are right.
Diagonal of a rhombus bisect each other and also perpendicular to each other.
More important:-
Area of rhombus = b × h
Perimeter of rhombus = 4 × side
where,
b = base
h = height
p = perimeter
a = area