Question

Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm.If one of it's diagonal is 8 cm long,find the length of the other diagonal.(Maths Question.Give appropriate answer.)

Answer 1

we know that - diagonal of rhombus bisect each other.at 90°.
so, 5² = 4² +x²
√25-16 = x
√9 = x
x= 3cm.
so , lenght of other dia. = 6 cm .ans.

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =5×4.8=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.