Question

find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 CM if one of its diagonal is 8 cm long find the length of the Other diagonal​

Answer 1

Answer:

Area of rhombus = Base × Height =

2

1

×Product of diagonals

⇒5×4.8=

2

1

×(8×x)

⇒24=

2

1

×(8×x)

⇒x=6 cm

Explanation:

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Answer 2

Explanation:

Background

Since given figure is a special llgm.

We say ::: AREA(A)=Base(B)*Height(H)

Also because it rhombus Area is also (A)=1/2*D1*D2

Where D1 and D2 are Respective diagonals

Given information

H= 4.8

D1= 8

B= 5

Required :: D2

Formulation

=B*H=1/2*D1*D2

=4.8*5=1/2*8*D2

=4.8*5*2=8*D2

=48=8*D2

=48/8=D2

D2=6

ANSWER

Diagonal = 6