Question

Find the area of a rhombus whose side is 5 cm and whose altitude is 4.8 cm. If one of its diagonals is 8 cm long, find the length of the other diagonal.​

Answer 1

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Answer 2

Answer:

$area \: of \: rhombus \: = base \times height = \frac{1}{2} \:× product \: of \: diagonals \\ 5 \times 4.8 = \frac{1}{2} \times (8 \times x) \\ 24 = \frac{1}{2} \times (8 \times x) \\ x = 6cm$

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