Question

find the area of a rhombus whose side is 5cm and whose altitude is 4 . 8 cm . if one of its diagonals is 8cm long, find the length of the other diagonal.​

Answer 1

Step-by-step explanation:

length of the one diagonal d1 = 8 cm

length of the other diagonal d2 = altitude= 4.5 cm

area of the rhombus = ½*d1 * d2

= ½* 8*4.5

= 4*4.5

= 18.0 18 cm²

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =5×4.8=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.