Question

Find the area of a rhombus whose side is 6
and altitude is 4 cm .if one of its diagonal
is 8 cm long. find the length of the other
diagonal​

Answer 1

Answer:

side=6cm

height=4cm

Areaofa∥gm=base×height

=6×4

=24cm  

2

 

Areaofarhombus=  

2

1

​  

×d  

1

​  

×d  

2

​  

 

⇒24=  

2

1

​  

×8×d  

2

​  

 

⇒d  

2

​  

=  

8

24×2

​  

 

∴d  

2

​  

=6

Hence,other length is 6cm.

​

Step-by-step explanation:

Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =6×4=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.