Question

find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm.If one of its diagonal is 8 cm long, find the length of the other diagonal.​

Answer 1

Answer:

Wehave

side=6cm

height=4cm

Areaofa∥gm=base×height

=6×4

=24cm

2

Areaofarhombus=

2

1

×d

1

×d

2

⇒24=

2

1

×8×d

2

⇒d

2

=

8

24×2

∴d

2

=6

Hence,otherlengthis6cm.

Step-by-step explanation:

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Answer 2

Since,a rhombus is also a kind of a parallelogram.

Formula of area of rhombus =Base×Altitude

Putting values, we have

Area of rhombus =6×4=24

Since, Area of rhombus is 24 cm².

Also,formula for area of rhombus =$\frac{1}{2}×d_1d_2$

Given,Length of one diagonal =$d_1$=8

Let length of other diagonal =$d_2$

After substituting the values, we get

$24=\frac{1}{2}×8×d_2$

$24=4×d_2$

$4×d_2=24$

$d_2=\frac{24}{4}$

$d_2=6$

Hence, length of other diagonal is 6 cm.