Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. if one of its diagonal is 8 cm long, find the length of another diagonal.
Answers
Answer:
Area of rhombus = 24 cm²
Length of the other diagonal = 6 cm.
Step-by-step explanation:
Hi,
Given the side of the rhombus, b = 6 cm
Also, Given the altitude of rhombus , h = 4 cm,
Area of the rhombus when base(side) and altitude(h)
are given is given by A = base * height
Thus, Area of rhombus = 6 * 4 cm²
Area of rhombus = 24 cm².
Given one of the diagonal is of length 8 cm,
Let d₁ = 8 cm.
Let the length of the other diagonal be d₂.
If d₁, d₂ length of the diagonals are known, then
Area of rhombus is given by A = 1/2*d₁*d₂,
But we know, A = 24
Hence, 1/2*d₁*d₂ = 24
1/2*8*d₂ = 24
d₂ = 6 cm.
Hence, length of the other diagonal of rhombus
is 6 cm.
Hope, it helps !
Answer:
Area = 24 cm²
Diagonal = 6 cm
Step-by-step explanation:
Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. if one of its diagonal is 8 cm long, find the length of another diagonal.
Area of rhombus = Length of Side * Altitude
=> Area of rhombus = 6 * 4 = 24 cm²
Also area of rhombus = (1/2) * Diagonal1 * Diagonal2
=> 24 = (1/2) * 8 * Diagonal2
=> 24 = 4 * Diagonal2
=> Diagonal2 = 24/4
=> Diagonal2 = 6 cm
Hence Area = 24 cm² & Other Diagonal = 6 cm