Math, asked by ha3Me7Shminut, 1 year ago

Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. if one of its diagonal is 8 cm long, find the length of another diagonal.

Answers

Answered by VEDULAKRISHNACHAITAN
317

Answer:

Area of rhombus = 24 cm²

Length of the other diagonal = 6 cm.

Step-by-step explanation:

Hi,

Given the side of the rhombus, b = 6 cm

Also, Given the altitude of rhombus , h = 4 cm,

Area of the rhombus when base(side) and altitude(h)

are given is given by A = base * height

Thus, Area of rhombus = 6 * 4  cm²

Area of rhombus = 24 cm².

Given one of the diagonal is of length  8 cm,

Let d₁ = 8 cm.

Let the length of the other diagonal be d₂.

If d₁, d₂ length of the diagonals are known, then

Area of rhombus is given by A = 1/2*d₁*d₂,

But we know, A = 24

Hence, 1/2*d₁*d₂ = 24

1/2*8*d₂ = 24

d₂ = 6 cm.

Hence, length of the other diagonal of rhombus

is 6 cm.

Hope, it helps !

Answered by amitnrw
168

Answer:

Area = 24 cm²

Diagonal = 6 cm

Step-by-step explanation:

Find the area of a rhombus whose side is 6 cm and whose altitude is 4 cm. if one of its diagonal is 8 cm long, find the length of another diagonal.

Area of rhombus =  Length of Side * Altitude

=> Area of rhombus = 6 * 4 = 24 cm²

Also area of rhombus = (1/2) * Diagonal1 * Diagonal2

=> 24 = (1/2) * 8 * Diagonal2

=> 24 = 4 * Diagonal2

=> Diagonal2 = 24/4

=> Diagonal2 = 6 cm

Hence Area = 24 cm² & Other Diagonal = 6 cm

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