find the area of a rhombus whose side is 6cm and whose altitude is 4cm.if one of its diagonal is 8cm long, find the other diagonal.
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Given side = 6cm.
Altitude = 4cm.
We know that area of the rhombus = Base * Height
= 6 * 4
= 24cm^2.
Therefore the area of the rhombus = 24cm^2.
Given that length of the one diagonal = 8cm.
We know that Area of the rhombus = 1/2 * d1 * d2
24 = 1/2 * 8 * d2
24 = 4 * d2
d2 = 6cm.
Therefore the length of the other diagonal = 6cm.
Hope this helps!
Altitude = 4cm.
We know that area of the rhombus = Base * Height
= 6 * 4
= 24cm^2.
Therefore the area of the rhombus = 24cm^2.
Given that length of the one diagonal = 8cm.
We know that Area of the rhombus = 1/2 * d1 * d2
24 = 1/2 * 8 * d2
24 = 4 * d2
d2 = 6cm.
Therefore the length of the other diagonal = 6cm.
Hope this helps!
HarshSaini11:
very correct.. thanx Sir
welcome
there's a diagonal right? I just had a question... can we find the area of the two triangles formed by the diagonal?
that is 1/2 base * height +1/2 base *height
I mean to find the area of the rhombus?
24 is the right answer
yes you can do that
take the diagonal , half it.
and use the formula
thank you
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