Question

Find the area of a rhombus whose side is 8 cm and whose altitude is 7 cm.If one its diagonals is 16cm,find the length of the other diagonal.

Answer 1

Heya mate,Here is ur answer

Side (let it be base bcz each side is equal to another)=8 cm.

Height=7cm

Area of rhombus=
$base \times height$

$= 8 \times 7$

$= 56 \: cm {}^{2}$

We know that

Area of rhombus
$= \frac{1}{2} \times diagonal \: 1 \times diagonal \: 2$

Equating the area.

$56 = \frac{1}{2} \times 16 \times diagonal \: 2$

$56 = 8 \times diagonal \: 2$

$\frac{56}{8} = diagonal \: 2$

$7 \: cm = diagonal \: 2$

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@Laughterqueen

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Answer 2

Answer:

Area of the rhombus = Side × Length of the altitude  

= 5*4.8

= 24 sq cm  

Now,

Let the length of the other diagonal = x

It is known that the area of a rhombus is half the product of its diagonals.  

∴ (1/2) × 8 × x = 24

⇒ 4x = 24

⇒ x = 6 cm

The length of the other diagonal is 6 cm.