Question

Find the area of a rhombus whose side is 8cm and whose altitude is 6cm .If one of the diagonals is 10cm long, find the length of other diagonal

Answer 1

given :-

side of the rhombus = 8cm

altitude of the rhombus = 6cm

therefore it's area = b × h (since rhombus is also a parallelogram)

= 8 × 6

= 48cm²

another formula for the area of a rhombus is 1/2 × d1 × d2 where d1 and d2 are the diagonals of the Rhombus.

we are given the length of one diagonal that's 10cm

=> 1/2 × d1 × d2 = 48cm²

=> 1/2 × 10 × d2 = 48cm²

=> 5 × d2 = 48cm²

=> d2 = 48/5

=> d2 = 9.6cm

hence, the length of another diagonal is 9.6cm

Answer 2

Answer:

48sq.cm and 9.6cm

Step-by-step explanation:

side of the rhombus = 8cm

altitude of the rhombus = 6cm

therefore, the area = b×h (since, rhombus is also a parallelogram)

= (8×6)sq. cm

=48sq.cm

so the area is 48sq.cm

now, one of the diagonals = 10cm

area of the rhombus = 1/2 (d1×d2)

=> 1/2×10×d2 = 48sq.cm

=> 5×d2 = 48sq.cm

=> d2 = 48/5

=> d2 = 9.6cm

so, the other length of the diagonal is 9.6cm