Question

Find the area of a rhombus whose side is is 5 cm and whose altitude is 4.8 if one of its diagonal is 8 cm long find the length of the other diagonal...?​

Answer 1

$\huge \underline{ \mathbb{SOLUTION:-}}$

Given:

• Side of the rhombus = 5cm
• Altitude of the rhombus = 48cm
• Length of its one diagonal = 8cm

Need to find:

• Length of the other diagonal

Step by step explanation:

Area of the rhombus = side×length of the altitude

=> 5×48

=> 24 sq cm

Now,

Let the length of the other diagonal be x

As we know that

Area of rhombus = half the product of its diagonals

Therefore,

$\large \implies{ \frac{1}{2} \times 8 \times x = 24} \\ \large \implies{4x = 24} \\ \large \implies{x = \frac{24}{4} } \\ \large \implies{ \bold{x = 6cm}}$

Hence, the length of the other diagonal is 6cm.

Answer 2

Answer:

first apply pythogorus theorem

8/2=4

5*5-4*4

25-16=9

square root of 9=3

3+3=6

one more diagonal is 6cm

formula of area of rhombus is =1/2*product of it's diagonals

1/2*6*8=24cm square