Question

Find the area of a Rhombus with diagonals 25 cm and 48 cm.​

Answer 1

Given :

• Diagonals = 25cm and 48cm

To Find :

• Area of a Rhombus

Solution :

We know that,

A Rhombus has 2 diagonals

Lets take 25cm and 48cm as,

• Diagonal₁ ( d₁ ) = 25cm
• Diagonal₂ ( d₂ ) = 48cm

⇒ Area of a Rhombus = 1/2 × d₁ × d₂

⇒ Area of a Rhombus = 1/2 × 25 × 48

⇒ Area of a Rhombus = 25 × 24

⇒ Area of a Rhombus = 600cm²

•°• Area of a Rhombus = 600cm²

★ More to know :

Using Diagonals :

• A = 1/2 × d₁ × d₂

Using Base and Height :

• A = b × h

Using Trignometry :

• A = b² × Sin(a)

____________________________________

Answer 2

$\begin{gathered}{\underline{\underline{\Huge{\textsf{\textbf{\red{Solution:}}}}}}}\end{gathered}$

$\large\sf\bigstar{Given:}$

$\large\sf\bold{Diagonals \: = 25cm \: and \: 48 cm}$

$\large\sf\bold\bigstar{To \: Find \implies}$

$\large\sf{Area \: Of \: Rhombus}$

$\large\sf\bigstar{Using \: Formula \implies}$

$\rightarrow\sf\bold{\frac{1}{2} × Diagonal \: 1 × Diagonal \: 2}$

$\large \sf\bold\bigstar{We \: know \: that,}$

$\rightarrow \sf\bold{Diagonal \: 1 \: = 25cm}$

$\rightarrow\sf\bold{ Diagonal \: 2 \: = 48cm}$

$\sf\bold{Let's \: Find \: The \: Area \: Of \: Rhombus\implies}$

$\sf\bold\rightarrow{\frac{1}{2} × Diagonal \: 1 × Diagonal \: 2}$

$\sf\bold\rightarrow{\frac{1}{2} × 25cm × 48cm}$

$\sf\bold\rightarrow{\frac{1}{1} × 25cm × 24cm}$

$\sf\bold\rightarrow{\frac{1}{1} × 600cm}$

$\sf\bold\rightarrow{600 cm}$

$\large\sf\fbox{Final \: Answer \: = \: 600cm}$

$\large\sf\bold\star{More \: Used \: Formulas\implies}$

$\sf\red{Using \: Diagonals \: = A = \frac{1}{2} × Diagonal \: 1 × \: Diagonal \: 2}$

$\sf\red{Using \: Base \: And \: Height= \: A= \: B \times H}$

$\sf\red{Using \: Trigonometry \: = \: A \: = \: b² \times Sin(a)}$

$\sf\blue\bigstar{Related \: More \: Questions\implies}$

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