find the area of a rhombus with each side is 13m. and one diagnol is 10 m.
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One side rhombus = 13 cm
length of one diagonal = 10 cm
property to use: diagonals of rhombus bisect each other at 90 degree
taking 1/4 portion of rhombus (triangle)
base = 5 cm (half of diagonal)
hypotnuse = 13 cm
for perpendicular use pythagoras theorem
on putting the values in the equation and then solving it we get perpendicular(p)= 12cm
therefore diagonal = 2p= 24cm And after further solving we get 1/2 (24)(10) =120
length of one diagonal = 10 cm
property to use: diagonals of rhombus bisect each other at 90 degree
taking 1/4 portion of rhombus (triangle)
base = 5 cm (half of diagonal)
hypotnuse = 13 cm
for perpendicular use pythagoras theorem
on putting the values in the equation and then solving it we get perpendicular(p)= 12cm
therefore diagonal = 2p= 24cm And after further solving we get 1/2 (24)(10) =120
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iana:
plz ans it properly how to solve it ur ans tht is coming 120 is correct
See firstly we have find lenght of 2nd diagonal of rombus
As shown above
Is it clear
Till this
yes
After this we use the formula of finding are of rombus
As first diagonal lengthbis give 10
thnks understoood
Did u get the answer
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