Question

find the area of a rhombus with each side measure 20 cm and one of its diagonal is 32

cm

Answer 1

Let we can name the rhombus as abcd and midpoint as o.  In rhombus all the sides are equal so.. Ab=bc=cd=da=20cm. On of its diagonal is 32cm.let db be 32cm.   Therefore do=ob=16cm. In triangle aob,  Ab=20cm. Ob=16cm Absquare =ao square+ob square (Pythagoras theorem) 20 square=ao square +16 square. 400=ao square +256. Ao square =400-256 Ao square =144 Ao=root 144  Ao=12cm  Therefore =ao+oc=a.c. =12+12 =24cm=ac  Area of rhombus =1/2*d1*d2 =1/2*ab*a.c. =1/2*32*24 =16*24 =384cm square   Pls mark as brainliest