Math, asked by Lipi12, 1 day ago

Find the area of a rhombus with one diagonal equal to twice the other diagonal. What is the relationship between the area of this rhombus and the area of a square with side length equal to the smaller diagonal?
Please answer ASAP

Answers

Answered by parshvgandhi9151
0

Answer:

The area of a rhombus can be defined as the amount of space enclosed by a rhombus in a two-dimensional space. To recall, a rhombus is a type of quadrilateral projected on a two dimensional (2D) plane, having four sides that are equal in length and are congruent.

Answered by deepsinghdhiman27
0

Answer:

Area of rhombus =

2

1

d

1

d

2

Let one diagonal =x

=

2

1

×(x)(2x)=x

2

A=x

2

Let side of rhombus =y & height =h

ΔBFC side BF=

y

2

−h

2

In ΔAFC,(y+

y

2

−h

2

)

2

+h

2

(AC)

2

=4x

2

ΔDEB(y−

y

2

−h

2

)

2

+h

2

=(BD)

2

=x

2

Adding 4y

2

=5x

2

y=

4

5x

2

=

2

5A

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