find the area of a right angle in which base =7cm and hypotenuse is 25cm .if BD! AC ,find BD ?
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Answered by
25
we have,
hypotenuse =25cm
base=7cm
height=?
By pythagoras theorem
(hypotenuse)^2=
(base)^2+(height)^2
(25)^2=(7)^2+(height)^2
625=49+(height)^2
(height)^2=576
height=24cm
Area of triangle =1/2×b×h
Area of triangle=1/2×7×24
Area of triangle=7×12
Area of triangle=84sq.cm
hope this helps # ! ! !
hypotenuse =25cm
base=7cm
height=?
By pythagoras theorem
(hypotenuse)^2=
(base)^2+(height)^2
(25)^2=(7)^2+(height)^2
625=49+(height)^2
(height)^2=576
height=24cm
Area of triangle =1/2×b×h
Area of triangle=1/2×7×24
Area of triangle=7×12
Area of triangle=84sq.cm
hope this helps # ! ! !
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5
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