Find the area of a right angle triangle ABC in which perpendicular AB=3 cm and Base BC=4 cm.
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Step-by-step explanation:
If the angle B = 90°, AC is the hypotenuse and is equal to
5 cm by Pythagoras theorem.
Area of ∆ ABC = (1/2)(AB)(BC)
= (1/2)(3)(4) = 6 cm^2 …….(1)
If the hypotenuse is taken as the base and BD as the
height then the area of the ∆AB
= (1/2)(AC)(BD)
=> (1/2)(5)(BD) = 6 from (1)
=> BD = 12/5 = 2.4 cm.
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