Question

find the area of a right angle triangle if it's perpendicular is 60cm and it's hypotenuse is 61cm

Answer 1

area of a right angled triangle is 1/2*b*h
so first we have to find base
so we will follow pythogoreans theorum
${b}^{2} = {h}^{2} - {p }^{2} \\ {b}^{2} = {61}^{2} - {60}^{2} \\ {b}^{2} = 3721 - 3600 \\ {b}^{2} = 121 \\ b = 11$
so we got our base
so area =1/2*11*60=330

Answer 2

Answer:

330  cm sq

Step-by-step explanation:

area of a right angled triangle is 1/2*b*h  

so first we have to find base    

so we will follow pythogoreans theoram

b^2   = h^2 - p^2  

b^2 = 61^2 - 60^2

b^2 = 3721 - 3600

b^2 = 121

b = 11

base   = 11

Area =1/2(Base × Perpendicular)    

Area =1/2(60×11)

Area =330 cm sq.