find the area of a right angle triangle whose base is 15cm and hypoteneois is 21 cm
Answers
Answered by
4
Hey !!
Base = 15cm
heighpoteneois = 21 cm
p = √h²-b²
p = √21²-15²
p = √441 - 225
p = √216
p = 14.6969 ....
Area of right traingle = 1/2base ×perpendicular /height
=> 1/2×15×14.6969385
=> 110.227039cm² Answer
*************************************
Hope it helps you !!!
@Rajukumar111
Base = 15cm
heighpoteneois = 21 cm
p = √h²-b²
p = √21²-15²
p = √441 - 225
p = √216
p = 14.6969 ....
Area of right traingle = 1/2base ×perpendicular /height
=> 1/2×15×14.6969385
=> 110.227039cm² Answer
*************************************
Hope it helps you !!!
@Rajukumar111
Answered by
1
base-15cm,hypotenuse-21cm perpendicular-√h^2-b^2=√441-225=√216 so area 1/2×B×H(perpendicular)=1/2×15×√216=110.23cm^2 approx. hope it helps
Similar questions