Find the area of a right angle triangle whose hypotenuse is 13 cm and one side is 5 cm.
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Answered by
24
Are of a triangle = 1/2 × base × height
Hypotenuse ^2 = base ^2 + side ^2
13^2 = base^2 + 5^2
Base^2 = 169-25
Base ^2 = 144
Base = 12 cm
Now , area of a triangle = 1/2 × base × height
Area = 1/2 × 12 × 5
Area = 30 cm^2
Hypotenuse ^2 = base ^2 + side ^2
13^2 = base^2 + 5^2
Base^2 = 169-25
Base ^2 = 144
Base = 12 cm
Now , area of a triangle = 1/2 × base × height
Area = 1/2 × 12 × 5
Area = 30 cm^2
Answered by
4
H^2=P^2+B^2 (by Pythagoras)
(13)^2=(5)^2+B^2
169=25+B^2
169-25=B^2
144=B^2
√144=B
B=12
Now, area of right triangle=1/2B*H
1/2*12*5
30
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