Question

find the area of a right angle triangle with hypotenuse 25 cm and base 7 cm

Answer 1

${25}^{2} - {7}^{2} = 625 - 49 = 576 \\ \sqrt{576 } = 24 \\area = \frac{1}{2} \times base \times height \\ = \frac{1}{2} \times 24 \times 7 \\ = 84$

Answer 2

$hii.. \\ \\ by \: pythagoras \: theorem.. \\ \\ = > height = \sqrt{ {hypotenuse }^{2} - {base}^{2} } \\ = > height = \sqrt{ {25}^{2} - {7}^{2} } = \sqrt{625 - 49} = 24 \\ \\ = > now...area \: of \: triangle = \frac{1}{2} \times base \times height \\ \\ = > \frac{1}{2} \times 7 \times 24 = 84 \: {cm}^{2} \\ \\ hope \: this \: helps :)$