Question

find the area of a right angled triangle phot whose Base in 6m and altitude is 5m respectively find the cost of putting tiles pre sq.m RS100​

Answer 1

Question:-

find the area of a right angled triangle phot whose Base in 6m and altitude is 5m respectively find the cost of putting tiles pre sq.m RS100??

Answer :-

Given:-

Base :- 6m

Altitude :- 5m

So,

The Formula Of Finding The Area Of ∆

$area \: of \: \triangle \longrightarrow \frac{1}{2} \times base \: \times \: height \\ \\ \longrightarrow \frac{1}{2} \times 6 \times 5 \\ \\ \longrightarrow \frac{1}{2} \times 30 \\ \\ \longrightarrow \frac{30}{2} \\ \\ \longrightarrow 15m ^{2}$

So, The Final Answer Is

$\longrightarrow 15m ^{2}$

Answer 2

Base of the plot = 6 m

Altitude = 5 m

We know,

Area of a △ = $\dfrac{bh}{2}$

∴ Area = ½ × (6 m)(5 m)

⇒ Area = (3 m)(5 m)

⇒ Area = 15 m².

Now, rate of putting tiles = Rs 100/m²

∴ Total cost = (Rs 100/m²)(15 m²)

⇒ Total cost = Rs 1500 (ans.)

ALITER:-

Since base and height are given, then you can find the hypotenuse by the Pythagoras theorem, i.e.,

$a^2 + b^2 = c^2$.

And then, put the values in Heron's formula, i.e.,

$\sqrt{s(s - a)(s - b)(s - c) }$.

Nextly, you'll get the area. Subsiquently, multiply the area with the rate.