Find the area of a right-angled triangle, the radius of whose
circumcircle measures 8 cm and the altitude drawn to the hypotenuse
measures 6 cm.
Answers
Radius = 8 cm
Altitude = 6 cm
In a right-angled triangle the hypotenuse
is the diameter of circumcircle.
Hypotenuse = 2 × Radius
= 2 × 8 cm
= 16 cm
Now,
Hypoteneus = base
Altitude to the hypotheneus = height
Area of a triangle = 1/2 × Base × Height
= 1/2 × 16 cm × 6 cm
= 1/2 × 96 cm2
= 48 cm2
Answer:
- Area of the given triangle is 48 cm².
Given :
- Radius = 8 cm
- Its Altitude = 6 cm
To find :
- Area of the given triangle =?
Step-by-step explanation:
Radius = 8 cm [Given]
And, Diameter = 2r = 2 x 8 = 16 cm
We know in a right - angled triangle the hypotenuse is equal to the diameter.
So, Hypotenuse = 16 cm
Now, Hypotenuse = Base = 16 cm
And, Altitude = Height = 6 cm [Given]
Now,
Area of triangle = 1/2×b×h
Substituting the values in the above formula, we get,
= 1/2×16×6
= 1/2×96
= 96/2
= 48cm²
Hence, area of the given triangle is 48 CM².