Find the area of a right-angled triangle whose base is 15 cm and altitude XYZ is a right-angled triangle with ZX = 90° , XY = 9 cm, and YZ = 12 cm. OX is perpendicular to YZ Find OX. Х Y 0 Z
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Step-by-step explanation:
In a right triangle, by Pythagoras theorem:
(Hypotenuse)
2
=(Perpendicular)
2
+(Base)
2
AC
2
=AB
2
+BC
2
2 +15 =17
=64+225=289
Taking square roots on both sides, we get
∴HypotenuseAC=
289
=17 cm.
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