Find the area of a right angled triangle whose hypotenuse is 10 cm and base 8 cm.
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Hypotenuse =10cm
Base =8cm
Height =?
Let height be x cm.
According to Pythagoras theorm,
(Hyp)^2=(base)^2+(height)^2
(10)^2=(8)^2+(x)^2
100=64+x^2
100-64=(x)^2
36=(x)^2
(6)^2=(x)^2
6=x
Thus,
Height is 6 cm.
Area of triangle =1/2×base×height =1/2×8×6 =4×6 =24cm^2
Thus,
Area of triangle is 24 cm^2
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Base =8cm
Height =?
Let height be x cm.
According to Pythagoras theorm,
(Hyp)^2=(base)^2+(height)^2
(10)^2=(8)^2+(x)^2
100=64+x^2
100-64=(x)^2
36=(x)^2
(6)^2=(x)^2
6=x
Thus,
Height is 6 cm.
Area of triangle =1/2×base×height =1/2×8×6 =4×6 =24cm^2
Thus,
Area of triangle is 24 cm^2
HOPE IT WILL HELP U...
PLZ MARK IT AS BRAINLIEST ANSWER..
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