find the area of a right angled triangle whose hypotenuse is 13 cm long and one of its legs is 12 cm long
Answers
Answered by
38
(hypotenuse )square= side first square + side second square
169=144+side second square
169-144=side second square
25=side second square
5=side second
area of right angled triangle=1/2* product of first side and second side
area of right angled triangle=1/2*5*12
area of right angled triangle=30sq.cm
169=144+side second square
169-144=side second square
25=side second square
5=side second
area of right angled triangle=1/2* product of first side and second side
area of right angled triangle=1/2*5*12
area of right angled triangle=30sq.cm
Answered by
4
Answer:
Hey mate,
Here it issss!
Don't judge my handwriting tho- cuz I wrote it is in a speed of light (hehe...just a part of speech) due to some probs! However...tq
Hope it helps ya!!!
Attachments:
Similar questions
World Languages,
7 months ago
Computer Science,
7 months ago
Physics,
7 months ago
Science,
1 year ago
Science,
1 year ago
English,
1 year ago