Question

Find the area of a right angled triangle whose hypotenuse is 5 m and base is 4 m .

Answer 1

Hypotenuse=H=5m
Base=B=4m
Perpendicular=P=?
Put phythogorous theorem
(H)^2=(P)^2+(B)^2
5^2=P^2+4^2
25=P^2+16
P^2=25-16
P^2=9
P=√9
P=3.
Area of triangle=1/2*base*height

Answer 2

Given,

A right-angled triangle, with

hypotenuse = 5 m,

base = 4 m.

To find,

Area of the triangle.

Solution,

Here, the base and hypotenuse of the triangle are given. So, firstly we need to find the height to determine the area of the triangle.

Using Pythagoras theorem,

$h^2=b^2+p^2$

Where,

h = hypotenuse,

b = base, and,

p = height or perpendicular.

For the given triangle,

h = 5 m, b = 4 m.

⇒ $(5)^2=(4)^2+p^2$

Rearranging and simplifying the above equation,

$p=\sqrt{25-16}$

⇒ $p = \sqrt{9}$

⇒ p = 3 m.

So, in the triangle, we have,

base = 4 m,

height = 3 m.

Now, the area of the triangle (A) can be found using

$A=\frac{1}{2} \times base \times height$

⇒ $A=\frac{1}{2} \times 4 \times 3$

⇒ A = 6 m².

Therefore, the area of the given right-angled triangle will be 6 m².