Question

find the area of a right angled triangle whose hypotenuse is 13cm long and one of its legs is 12cm long

Answer 1

h^2=b^2+p^2
13^2=12^2+p^2
169=144+p^2
169-144=p^2
25=p^2
p=5
1/2×12×5
=30..ans...
HOPE IT HELPS



area=1/2×b×h
=

Answer 2

Base=5cm
S=15cm
A=
$\sqrt{s{s - a} {s - b}{s - c}}$
$\sqrt{15(15 - 13)(15 - 12)(15 - 5)}$
$\sqrt{15 \times 2 \times 3 \times 10}$
$\sqrt{900}$
30cm^2